Tentukan hasil dari:
[tex] \frac{ {3}^{x + 2} \times {6}^{ - 4} } { {6}^{x - 1} } [/tex]
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[tex] \frac{ {3}^{x + 2} \times {6}^{ - 4} } { {6}^{x - 1} } [/tex]
[tex] \frac{ {3}^{x + 2} \times {6}^{ - 4} }{ {6}^{x - 1} } = \frac{ {3}^{x + 2} }{ {6}^{x - 1} \times {6}^{4} } [/tex]
[tex] = \frac{ {3}^{x + 2} }{ {6}^{x - 1 + 4} } [/tex]
[tex] = \frac{ {3}^{x + 2} }{ {6}^{x + 3} } [/tex]
[tex] = \frac{ {3}^{x + 2} }{ {(2 \times 3)}^{x + 3} } [/tex]
[tex] = \frac{ {3}^{x + 2} }{ {2}^{x + 3} \times {3}^{x + 3} } [/tex]
[tex] = \frac{1}{ {2}^{x + 3} \times {3}^{x + 3 - (x + 2)} } [/tex]
[tex] = \frac{1}{ {2}^{x + 3} \times {3}^{x + 3 - x - 2} } [/tex]
[tex] = \frac{1}{ {2}^{x + 3} \times {3}^{x - x + 3 - 2} } [/tex]
[tex] = \frac{1}{ {2}^{x + 3} \times {3}^{0 + 1} } = \frac{1}{ {2}^{x + 3} \times {3}^{1} } = \frac{1}{3 \times {2}^{x + 3} } [/tex]
[answer.2.content]
